I c = 1.5 I R L for D = 0.33 I c = 2 I R L for D = 0.50 I c = 2.5 I R L f o r D = 0.60 Requires auxiliary power supplies for control circuit.Ĭross conduction of Q 1, Q 2 possible. Collector current reduced as a function of N 2/ N 1. Preferred to circuit F where high power required. V C R 1 = 2 V I N ( N 2 / N 1 ) V C R 2 = 2 V I N ( N 2 / N 1 ) V C R 1 = V C R 2 = V C R 3 = V C R 4 = V I N V C R 5 = V C R 6 = 2 V I N ( N 2 / N 1 ) I C R I = I C R 2 = ( I M A G / 2 ) ( τ / T ) I C R 3 = I C R 4 = ( I M A G / 2 ) ( τ / T ) I C R 5 = I C R 6 = I R L / 2 Requires auxiliary power supplies for control circuits. Poor transient response: High parts count. Collector current reduced by ratio of N 2/ N 1. Collector current reduced by turns ratio of transformer. V C R 1 = V C R 2 = V I N V C R 3 = V C R 4 = V I N ( N 2 / N 1 ) V C R I = V I N ( 1 + N 3 / N 1 ) V C R 3 = V I N ( N 2 / N 3 ) V C R 3 = V I N ( N 2 / N 1 ) I C R I = I C R 2 = ( I M A G / 2 ) ( τ / T ) I C R I = I M A G / 2 ) ( τ / T ) I C R 2 = I R L ( τ / T ) I C R 3 = I R L ( T − τ ) / T I C M A X = ( N 2 / N 1 ) ( I R L + Δ I L I / 2 ) + I M A G I C M A X = I R L ( N 2 / N 1 ) ( I R L + Δ I L I / 2 ) + I M A G Voltage inversion without using a transformer.
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